Answer:
Center: (3, 0)
Radius: 2√2
Step-by-step explanation:
The equation of a circle in standard form:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
(h, k) - center
r - radius
We have the equation:
[tex](x-3)^2+y^2=8\to(x-3)^2+(y-0)^2=(\sqrt8)^2[/tex]
Therefore
the center: [tex](3,\ 0)[/tex]
the radius: [tex]r=\sqrt8\to r=\sqrt{4\cdot2}\to r=\sqrt4\cdot\sqrt2\to r=2\sqrt2[/tex]
