Respuesta :
[tex]\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\[-0.5em] \hrulefill\\ r=5\\ s=\frac{25\pi }{3} \end{cases}\implies \cfrac{25\pi }{3}=5\theta \implies \cfrac{25\pi }{15}=\theta \implies \cfrac{5\pi }{3}=\theta[/tex]
