bm42400
bm42400 bm42400
  • 03-04-2019
  • Mathematics
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Use the x-intercept method to find all real solutions of the equation.
x^2-9x^2+23x+15=0

Use the xintercept method to find all real solutions of the equation x29x223x150 class=

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kudzordzifrancis
kudzordzifrancis kudzordzifrancis
  • 03-04-2019

Answer:

b.[tex]x=1,3,\:or\:5[/tex]

Step-by-step explanation:

The given equation is;

[tex]x^3-9x^2+23x-15=0[/tex]

To solve by the x-intercept method we need to graph the corresponding function using a graphing tool.

The corresponding function is

[tex]f(x)=x^3-9x^2+23x-15[/tex]

The solution to [tex]f(x)=x^3-9x^2+23x-15=0[/tex] is where the graph touches the x-axis.

We can see from the graph  that; the x-intercepts are;

(1,0),(3,0) and (5,0).

Therefore the real solutions are:

[tex]x=1,3,\:or\:5[/tex]

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