Answer:
[tex](y-1)=\frac{1}{3}(x-6)[/tex]
Step-by-step explanation:
The equation of the line in point-slope form is:
[tex](y-y_1)=m(x-x_1)[/tex]
Where m is the slope and [tex](x_1,y_1)[/tex] is a point of the line.
The slopes of two perpendicular lines are opposite reciprocal, then the other slope is:
m=[tex]\frac{1}{3}[/tex]
Substitute the slope and the given point into the equation, then you obtain:
[tex](y-1)=\frac{1}{3}(x-6)[/tex]
