Answer:
y = (x +5)² - 30 where vertex for the parabola is (-5,-30).
Step-by-step explanation:
We have given a function:
f(x) = x² + 10x - 5
We have to find the vertex form given form.
Let y = f(x)
y= x² + 10x - 5
The general vertex form :
y = a(x-h)²+h
First, we have to complete the square we have,
y= x² + 10x - 5
y = x² +2(x)(5)-5 +(5)²-(5)²
y = (x +5)²-5-25
y = (x +5)² - 30
y = (x +5)² - 30 where vertex for the parabola is (-5,-30).
