Answer:
Step-by-step explanation:
note :
( a + b )^3 = a^3 +b^3 +3 a²b +3b²a + b^3...(*)
the condition is : r = 1 and p=1
put : x= a and b = 1 in (*) you have :
(x + 1)^3 = x^3 +3x² +3x +1
the zeros is : x = - 1
bcause : x^3 +3x² +3x +1 = 0 .... (x + 1)^3 = 0 so : x = - 1
