Answer:
16xy²(1 -3x)(4y +3)
Step-by-step explanation:
4x is a common factor of the terms of the first factor. Taking that out gives ...
4x(1 -3x)(16y³ +12y²)
Similarlly, 4y² is a common factor of the terms of the second factor. Taking that out gives ...
4x(1 -3x)(4y²)(4y +3)
Combining the two monomial factors, we have ...
16xy²(1 -3x)(4y +3)
