All we have to do as the other question is PLUG IN the given X!
f(x)= [tex] \frac{3x^2-7}{4x^2-3} [/tex]
given x is 2
f(2)=[tex] \frac{3(2)^2-7}{4(2)^2-3} [/tex]
=[tex] \frac{12-7}{16-3} [/tex]
=[tex] \frac{5}{13} [/tex]
Answer=[tex] \frac{5}{13} [/tex]
