Sum of one-sided angles is 180°
[tex](16x+2)^\circ+(45x-5)^\circ=180^\circ\\(61x)^\circ=183^\circ\\ \\ x=3[/tex]
Sum of two adjacent supplementary angles = 180 .
[tex](26y)^\circ+(16x+2)^\circ=180^\circ\\ (26y)^\circ+(16\cdot3+2)^\circ=180^\circ\\ (26y)^\circ+50^\circ=180^\circ\\ (26y)^\circ=130^\circ\\ y=130^\circ:26^\circ\\y=5[/tex]
Answer: x=3 and y = 5.
