SophiaTrantina SophiaTrantina

02-10-2018
Mathematics

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what is the inverse of g(x)=(x-1)/4? is it g-1(x)=4x+1?

Respuesta :

03-10-2018

[tex]g(x)=\dfrac{x-1}{4}\to y=\dfrac{x-1}{4}\\\\\text{change x to y and y to x}\\\\x=\dfrac{y-1}{4}\ \ \ \ |\text{solve for y}\\\\\dfrac{y-1}{4}=x\ \ \ \ \ |\cdot4\\\\y-1=4x\ \ \ \ |+1\\\\y=4x+1\\\\\boxed{g^{-1}(x)=4x+1}[/tex]

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