Jasonwas8553 Jasonwas8553

04-09-2018
Physics

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A 0.22-caliber handgun fires a 29-g bullet at a velocity of 770. m/s. calculate the de broglie wavelength of the bullet.

Respuesta :

20-09-2018

solution:

[tex]\lambda =\frac{h}{mv}\\ h is planck's constant=6.626\times10^-34j.sec\\ m=mass=29g\\ =28\times10^-3kg\\ v=770m/sec\\ \lambda=\frac{6.626\times10^-34j.sec}{29\times10^-3\times770}\\[/tex]

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