amberpetty1866 amberpetty1866
  • 03-08-2018
  • Mathematics
contestada

If no digit may be used more than once, how many 5-digit numbers can be formed using only the digits 3, 8, 1, 2, 5, and 7?

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Pitymys Pitymys
  • 06-08-2018

The number of permutations of [tex] m(0\leq m\leq n) [/tex] objects from n objects is

[tex] P(m,n)=\frac{n!}{(n-m)!} [/tex]

Here 5 digits are chosen from 6 digits without replacement (order important).

The number of 5 digit numbers that can be formed is

[tex] \frac{6!}{(6-5)!} =6!=720 [/tex]

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