Here the expression is 11 to the second power over 1331 .
Which can be expressed as
[tex] \frac{11^2}{1331} [/tex]
And 1331 is the cube of 11, that is
[tex] \frac{11^2}{11^3} [/tex]
In case of division , we have to use quotient rule and subtract the powers, that is
[tex] 11^{2-3} = 11^{-1} [/tex]
Now we need to make the power positive and for that we have to flip the term. That is
[tex] \frac{1}{11} [/tex]
