Respuesta :

[tex] \frac{1-cos^2(\theta)}{cos^2(\theta)} [/tex]

we can use trigonometric identity

1-cos^2x =sin^2x

[tex] \frac{sin^2(\theta)}{cos^2(\theta)} [/tex]

now, we know that

tanx=sinx/cosx

[tex] =tan^2(\theta) [/tex].............Answer

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