Respuesta :

mathecoach

81^x^2 = 27^x

(3^4)^(x^2) = (3^3)^x

3^(4x^2) = 3^(3x)

4x^2 = 3x

4x^2 - 3x = 0

x(4x - 3) = 0

x = 0 oder x = 3/4

adioabiola

The solution to the equation 81^x^2=27^x is; x = 3/4

By indices;

  • 81^x^2=27^x

[tex] {3}^{ {4x}^{2} } = {3}^{3x} [/tex]

Therefore;

  • 4x² = 3x

  • 4x = 3

  • x = 3/4

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