A polyhedron has 8 vertices and 14 edges. How many faces must it have?

Question

04-06-2018
Mathematics

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A polyhedron has 8 vertices and 14 edges. How many faces must it have?

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calculista calculista · Answer 1 · 2018-06-13T02:50:50+02:00

calculista calculista

13-06-2018

we know that
The Euler's formula state that,
the number of vertices, minus the number of edges, plus the number of faces, is equal to two
V - E + F = 2
clear F
F=2-V+E
in this problem
V=8
E=14
F=?
so
F=2-8+14
F=8

the answer is
8 faces

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